CLA – Programming Essentials in C Quizzes Chapter 6 Assessment Online

What happens if you try to compile and run this program?

    void f(void) { 
    } 
    int main(void) { 
        int i; 
        i = f(); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(void) { 
    } 
    int main(void) { 
        int i; 
        i = f(); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    void f(int i) { 
        i++; 
    } 
    int main(void) { 
        int i = 1; 
        f(i); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(int i) {
       ++i;
        return i; 
    } 
    int main(void) { 
        int i = 1; 
        i = f(i); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(int i) { 
        return ++i; 
    } 
    int main(void) { 
        int i = 0; 
        i = f(f(i)); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int main(void) { 
        int i = 0; 
        { 
            int i = 1; 
            main.i = i; 
        } 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int i = 0; 
    void f(void) { 
        int i = 1; 
    } 
    int main(void) { 
        int i = 2; 
        f(); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int i = 0; 
    void f(void) { 
        int i = 1; 
    } 
    int main(void) { 
        f(); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int i = 1; 
    int *f(void) { 
        return &i; 
    } 
    int main(void) { 
        int i = 0; 
        i = *f(); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int i = 2; 
    int *f(void) { 
        return &i; 
    } 
    int main(void) { 
        int *i; 
        i = f(); 
        printf("%d",++(*i)); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int i = 0; 
    int *f(int *i) { 
        (*i)++; 
        return i; 
    } 
    int main(void) { 
        int i = 1; 
        i = *f(&i); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    struct S { 
        int S; 
    }; 
    int f(struct S s) { 
        return --s.S; 
    } 
    int main(void) { 
        int i; 
        struct S S = { 2 }; 
        i = f(S); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    struct S { 
        int S; 
    }; 
    int f(struct S *s) { 
        return --s.S; 
    } 
    int main(void) { 
        int i; 
        struct S S = { 2 }; 
        i = f(S); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(int t[\]) { 
        return t[0\] + t[2\]; 
    } 
    int main(void) { 
        int i,a[\] = { -2,-1,0,1,2 }; 
        i = f(a + 2); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(int t[\][\]) { 
        return t[0\][0\] + t[1\][0\]; 
    } 
    int main(void) { 
        int i,a[2\][2\] = { {-2,-1},{1,2} }; 
        i = f(a + 2); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(int t[2\][\]) { 
        return t[0\][0\] + t[1\][0\]; 
    } 
    int main(void) { 
        int i,a[2\][2\] = { {-2,-1},{1,2} }; 
        i = f(a + 2); 
        printf("%d",i); 
        return 0; 
    }

    #include <stdio.h> 
    int f(char t[\]) { 
        return t[1\] - t[0\]; 
    } 
    int main(void) { 
        int i = 2; 
        i -= f("ABDGK" + 1); 
        printf("%d",i); 
        return 0; 
    }

    #include <stdio.h> 
    int f(char t[\]) { 
        return t[1\] - t[0\]; 
    } 
    int main(void) { 
        int i = 2; 
        i -= f("ABDGK" + 1); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    int f(char t[\]) { 
        return t[0\] - t[-1\]; 
    } 
    int main(void) { 
        int i = 2; 
        i -= f("ABDGK" + 1); 
        printf("%d",i); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    #include <string.h> 
    void f(char *s,int i) { 
        *(s + i) = '\0'; 
    } 
    int main(void) { 
        char a[\] = { 'a','b','c','d' }; 
        f(a[1\],1); 
        printf("%d",strlen(a)); 
        return 0; 
    }

What happens if you try to compile and run this program?

    #include <stdio.h> 
    #include <string.h> 
    void f(char *s,int i) { 
        *(s + i) = '\0'; 
    } 
    int main(void) { 
        char a[\] = { 'a','b','c','d' }; 
        f(a+1,1); 
        printf("%d",strlen(a)); 
        return 0; 
    }